Newtonssoft Json将Json反序列化为自定义JObject

我从API得到了这个结构。

[
  {
    "Id": 611932,
    "ProjectId": 6079,
    "Title": "Issue1"
    "Viewpoints": [
      {
        "Id": 885758,
        "IssueId": 611932,
        "Pinpoint": {
          "Position": {
            "X": -32.452857971191406,
            "Y": -14.971426010131836,
            "Z": 9.1110143661499023
          }
        }
      },
      {
        "Id": 885764,
        "IssueId": 611932,
        "Pinpoint": {
          "Position": {
            "X": -21.042057037353516,
            "Y": -21.742080688476563,
            "Z": 7.72857141494751
          }
        }
      }
    ]
  },
  {
    "Id": 611931,
    "ProjectId": 6079,
    "Title": "Issue2",
    "Viewpoints": [
      {
        "Id": 885757,
        "IssueId": 611931
      },
      {
        "Id": 885762,
        "IssueId": 611931,
        "Pinpoint": {
          "Position": {
            "X": -29.135581970214844,
            "Y": -14.971452713012695,
            "Z": 7.0672616958618164
          }
        }
      }
    ]
  },
  {
    "Id": 611930,
    "ProjectId": 6079,
    "Title": "Issue3",
    "Viewpoints": [
      {
        "Id": 885756,
        "IssueId": 611930,
      }
    ]
  }
]

我希望能够构建一个包含所有；精确定位；“从全部”；“视点”；以对象的形式生成的结构如下所示（它不必位于数组中，也可以作为新对象包含）：

[
  {
    "Id": 885758,
    "IssueId": 611932,
    "Pinpoint": {
      "Position": {
        "X": -32.452857971191406,
        "Y": -14.971426010131836,
        "Z": 9.1110143661499023
      }
    }
  },
  {
    "Id": 885764,
    "IssueId": 611932,
    "Pinpoint": {
      "Position": {
        "X": -21.042057037353516,
        "Y": -21.742080688476563,
        "Z": 7.72857141494751
      }
    }
  },
  {
    "Id": 885762,
    "IssueId": 611931,
    "Pinpoint": {
      "Position": {
        "X": -29.135581970214844,
        "Y": -14.971452713012695,
        "Z": 7.0672616958618164
      }
    }
  }
]

请注意，我没有包含来自 Issue3 的“Viewpoint”数组和来自 issue2 的“Viewpoint”数组的一部分，因为它们不包含“Pinpoint”......

关于如何实现这一目标的任何想法？到目前为止，我已经尝试将每个“位置”对象添加到列表中，仅用于测试目的：

var jArray = JsonConvert.DeserializeObject<dynamic>(response.Content);

List<JToken> results = new List<JToken>();

foreach (JObject jObject in jArray)

{

    results.Add(new JObject(jObject["Viewpoints"].Children()["Pinpoint"]["Position"]));

}

但是我收到此错误：

无法将 Newtonsoft.Json.Linq.JObject 添加到 Newtonsoft.Json.Linq.JObject。